LynnetteC494600 LynnetteC494600
  • 25-10-2022
  • Mathematics
contestada

Solve the following polynomial equation by grouping and factoring. 36y^3āˆ’49y=0

Respuesta :

PinchosE607182 PinchosE607182
  • 25-10-2022

Given:

[tex]36y^3-49y=0[/tex]

solve for y:

[tex]\begin{gathered} 36y^3-49y=0 \\ y(36y^2-49)=0 \\ y=0;36y^2-49=0 \end{gathered}[/tex]

Value of y is zero and

[tex]\begin{gathered} 36y^2-49=0 \\ 36y^2=49 \\ y^2=\frac{49}{36} \\ y=\pm\sqrt[]{\frac{49}{36}} \\ y=\pm\sqrt[]{1.361111} \\ y=\pm1.166 \\ y=1.166,y=-1.166 \end{gathered}[/tex]

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