Given:
[tex]2x^3-5x^2-4x+3=0[/tex]Required:
To check that 3 is a root of the given equation.
Explanation:
Substitute x = 3 in the L.H.S. of the given equation.
[tex]\begin{gathered} 2(3)^3-5(3)^2-4(3)+3 \\ =2(27)-5(9)-12+3 \\ =54-45-12+3 \\ =57-57 \\ =0 \end{gathered}[/tex]This is the R.H.S.
Thus x=3 is a root of the given equatio.
Final Answer:
x= 3 is a root of the given equatio.
