Respuesta :

Remember that

[tex]\sin 2\theta=2\sin \theta\cos \theta[/tex]

Therefore,

[tex]\begin{gathered} \sin 2x-\sin 4x+\sin 6x=0 \\ \Rightarrow2\sin x\cos x-2\sin 2x\cos 2x+2\sin 3x\cos 3x=0 \end{gathered}[/tex]

Then,

[tex]undefined[/tex]

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