MaxtynK530670 MaxtynK530670
  • 25-10-2022
  • Mathematics
contestada

Find the 12th term in the arithmetic sequence an = 3 − 6(n − 1)a. -33b. -36c. -63d. -69

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SunM699412 SunM699412
  • 25-10-2022

Given:

[tex]a_n=3-6(n-1)[/tex]

Find-: 12th term of the sequence is

Sol:

[tex]\begin{gathered} a_n=3-6(n-1) \\ \end{gathered}[/tex]

Where,

[tex]\begin{gathered} n=\text{ term.} \\ \\ n=12 \end{gathered}[/tex]

Put the value then:

[tex]\begin{gathered} a_n=3-6(n-1) \\ \\ n=12 \\ \\ a_{12}=3-6(12-1) \\ \\ a_{12}=3-6(11) \\ \\ a_{12}=3-(6\times11) \\ \\ a_{12}=3-66 \\ \\ a_{12}=-63 \end{gathered}[/tex]

So 12th term is -63

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