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Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor. What is the theoretical yield of water, in moles, when 40. 0 g of ammonia and 50. 0 g of oxygen are mixed and allowed to react ?.

Respuesta :

when 40. 0 g of ammonia and 50. 0 g of oxygen are mixed and allowed to react .1.57 moles is the theoretical yield of water and 1.87 moles in balanced chemical

= 1*14.01 + 3*1.008

= 17.034 g/mol

mass(NH3)= 40.0 g

use:

number of mol of NH3,

n = molar mass of ammonia  

=(40 g)/(17.03 g/mol)

= 2.348 mol

Molar mass of O2 = 32 g/mol

mass(O2)= 50.0 g

use:

number of mol of O2,

n = molar mass of oxygen

=(50 g)/(32 g/mol)

1.562 mol  or 1.57 mol

Balanced chemical equation is:

4 NH₃ + 5 O₂ -> 6 H₂O + 4NO

4 mol of NH3 reacts with 5 mol of oxygen  for 2.348 mol of NH3, 2.935 mol of O2 is required  But we have 1.562 mol of O2  so,  use O2 in next calculation

According to balanced equation  mol of H2O formed = (6/5)* moles of oxygen

= (6/5)*1.562  

= 1.875 mol

= 1.87 mol

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