ANSWER:
Option c
[tex]h=-\frac{\operatorname{\ln}(0.62)}{0.079}[/tex]
STEP-BY-STEP EXPLANATION:
The function given in the statement is the following:
[tex]D(h)=615\cdot\:e^{-0.079h}[/tex]
If D(h) = 383, we substitute and solve for h, just like this:
[tex]\begin{gathered} 383=615\cdot \:e^{-0.079h} \\ \\ e^{-0.079h}=\frac{383}{615} \\ \\ \ln(e^{-0.079h})=\ln\left(\frac{383}{615}\right) \\ \\ -0.079h=\ln(0.62) \\ \\ h=-\frac{\ln(0.62)}{0.079} \end{gathered}[/tex]
Therefore, the correct answer is option c.
