contestada

The path of a punted football is modeled by
16/1225 x^2+7/5+1.5
where f(x) is the height (in feet) and x is the horizontal distance (in feet) from the point at which the ball is punted.
(a) How high is the ball when it is punted?

The path of a punted football is modeled by 161225 x27515 where fx is the height in feet and x is the horizontal distance in feet from the point at which the ba class=

Respuesta :

mhanifa

Answer:

  • (a) f(x) = 1.5 ft

-----------------------------

When the ball is punted the value of x is zero, therefore f(0) is:

  • f(0) = - 16/1225 × 0² + 7/5 × 0 + 1.5 = 1.5
ItzTds

Answer:

1.5 feet

Step-by-step explanation:

Given function,

→ f(x) = (-16/1225)x² + (7/5)x + 1.5

Required function,

→ f(x) = f(0)

→ f(0) = (-16/1225)x² + (7/5)x + 1.5

Now the needed height is,

→ (-16/1225)x² + (7/5)x + 1.5

→ (-16/1225)(0)² + (7/5)(0) + 1.5

→ 0 + 0 + 1.5

→ 1.5 feet

Hence, the height is 1.5 feet.

Otras preguntas