dorjac1398 dorjac1398
  • 22-03-2017
  • Mathematics
contestada

integrate the function.

∫(13tan²(xse)c²xdx

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LammettHash
LammettHash LammettHash
  • 22-03-2017
[tex]\displaystyle13\tan^2x\sec^2x\,\mathrm dx[/tex]

Let [tex]y=\tan x[/tex], so that [tex]\mathrm dy=\sec^2x\,\mathrm dx[/tex]. Then you have

[tex]\displaystyle13\int y^2\,\mathrm dy=\dfrac{13}3y^3+C[/tex]

and so

[tex]\displaystyle\int13\tan^2x\sec^2x\,\mathrm dx=\dfrac{13}3\tan^3x+C[/tex]
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