Z3uliaWierwerdocksb Z3uliaWierwerdocksb
  • 23-03-2017
  • Mathematics
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Given cscx =-5/2 between 270 and 360 find sin2x

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ghanami
ghanami ghanami
  • 23-03-2017
Hello : 
cscx = -5/2
1/sinx =-5/2
sinx=-2/5
sin²x+cos²x=1
4/25+cos²x=25/25
cos²x = 21/25
between 270 and 360 : cosx > 0          cosx=(√21)/5
but : sin2x =2sinx cosx
       sin2x = 2(-2/5)((√21)/5)
       sin2x = (-4√21)/25
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