mykingdaniel12
mykingdaniel12 mykingdaniel12
  • 26-04-2017
  • Mathematics
contestada

Write the equation of the given circle. center (3, 3) radius of 2

Respuesta :

isentrixx
isentrixx isentrixx
  • 26-04-2017
(x-3)^2 + (y-3)^2 = 2^2
Hope this helped
Answer Link
isyllus
isyllus isyllus
  • 10-05-2019

Answer:

General form:  [tex]x^2+y^2-6x-6y+14=0[/tex]

Standard form: [tex](x-3)^3+(y-3)^3=4[/tex]

Step-by-step explanation:

We are given a circle whose center (3,3) and radius 2

Formula:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where, (h,k) - > (3,3)

r = 2

Substitute the value of center and r into formula

[tex](x-3)^3+(y-3)^3=2^2[/tex]

[tex]x^2+9-6x+y^2+9-6y=4[/tex]

[tex]x^2+y^2-6x-6y+14=0[/tex]

Hence, The equation of circle is [tex]x^2+y^2-6x-6y+14=0[/tex]

Answer Link

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