Respuesta :

MissPhiladelphia
dy/dx= tanx, can be answered directly using the derivatives of trigonometric functions but this is how the answer is derived
         =(sinx/cosx) basic trigonometric function
         = [cosx cox+sinxsinx]/cos^2x
         =[cos^2x+sin^2x]/cos^2x
cos^2+sin^2x = 1 ; fundamental trigonometric identities
         = 1/cos^2x; reciprocal relations
          = sec^2x+C
The answer is letter B.sec^2x+C
The answer to this question is:

B) (sec x)^2 + C

Otras preguntas