Answer:
[tex]\frac{(x+7)}{3}[/tex]
Step-by-step explanation:
we have
[tex]\frac{x^{2}+12x+35}{3x+15}[/tex]
Convert the numerator in factored form
[tex]x^{2}+12x+35=(x+7)(x+5)[/tex]
Factor the term [tex]3[/tex] in the denominator
[tex]3x+15=3(x+5)[/tex]
Substitute
[tex]\frac{x^{2}+12x+35}{3x+15}=\frac{(x+7)(x+5)}{3(x+5)}=\frac{(x+7)}{3}[/tex]
