This is the concept of algebra, we are required to calculate for h(1) given that,
f(x)=2x^2-x+5; g(x)=3x^2-3x-2 and h(x)=f(x)+g(x)
here we proceed as follows;
h(x)=f(x)+g(x)
h(x)=2x^2-x+5+3x^2-3x-2
collecting the like terms we get;
h(x)=(2x^2+3x^2)+(-x-3x)+(5-2)
h(x)=5x^2-4x+3
thus
h(1)=5(1)^2-4(1)+3
h(1)=5-4+3
h(1)=8-4=4
hence;
h(1)=4
