eves073004ov89dj eves073004ov89dj
  • 22-01-2024
  • Mathematics
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Multiply the complex numbers (-7+i)(3-2i)

Respuesta :

jimthompson5910 jimthompson5910
  • 22-01-2024

Answer:  -19 + 17i

Work Shown

[tex](-7+i)(3-2i)\\\\=-7(3-2i)+i(3-2i)\\\\=-21+14i+3i-2i^2\\\\=-21+14i+3i-2(-1)\\\\=-21+14i+3i+2\\\\=(-21+2)+(14i+3i)\\\\=-19+17i[/tex]

In short,

[tex](-7+i)(3-2i)=-19+17i[/tex]

Notes:

  • Since [tex]i = \sqrt{-1}[/tex] both sides square to [tex]i^2 = -1[/tex]
  • I used GeoGebra to confirm the answer.
Answer Link

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