chip2
chip2
25-07-2015
Mathematics
contestada
what is the answer to this
Respuesta :
Panoyin
Panoyin
27-07-2015
[tex]\frac{2x - y}{4x^{2} + 4xy + y^{2}} / \frac{1}{(2x + y)^{2}} = \frac{2x - y}{4x^{2} + 4xy + y^{2}} * \frac{(2x + y)^{2}}{1} = \frac{2x - y}{(2x + y)^{2}} * \frac{(2x + y)^{2}}{1} = \frac{2x - y}{1} = 2x - y[/tex]
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