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24-10-2017
Mathematics
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chi3fcomm5nd
chi3fcomm5nd
24-10-2017
using the power of power rule you
[tex] { ({a}^{x}) }^{y} = {a}^{x \times y} [/tex]
thus
[tex] ({19}^{ \frac{1}{9} } )^9 = {19}^{ \frac{1}{9} \times 9 } = {19}^{1} = 19[/tex]
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