srijanmaskey09oye9xx srijanmaskey09oye9xx
  • 25-10-2017
  • Mathematics
contestada

Write an equation for a rational function with:

Vertical asymptotes at x = 3 and x = -4

x intercepts at x = -1 and x = 5

Horizontal asymptote at y = 6

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Catya
Catya Catya
  • 25-10-2017
Making a fraction is the easiest way to do this.

The x-intercepts give solutions to a problem that equals zero.
[tex]0 = (x-5)(x+1)[/tex]
The vertical asymptotes are values x cannot be, in a fraction the denominator can not be zero.
[tex]y = \frac{(x-5)(x+1)}{(x+4)(x-3)} [/tex]
Horizontal asymptotes are the values y approaches. This can be accomplished by making the leading term have a coefficient of 6
[tex]y = \frac{6(x-5)(x+1)}{(x+4)(x-3)} [/tex]


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