Artemis3775 Artemis3775
  • 24-01-2018
  • Chemistry
contestada

How many atoms of gold are in a pure gold coin weighing 12.0g?

Respuesta :

mlunguy
mlunguy mlunguy
  • 25-01-2018
12.0g x 1 mol / 63.546g = 0.188839581mol 

So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).

0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23 

Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 

That should be your answer!

Hope it helps!
xo
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