Answer:
The given function is
f(x)= 3 [tex]\sqrt\left- |x \right-2 |+6[/tex] ⇒[Absolute value function]
F(x)= 1. 3[tex]\sqrt {-(x-2)+6}[/tex] =[tex]3\sqrt {-x+2+6}=3\sqrt{-x+8}[/tex] when (x-2≥0→x≥2) ⇒[ Piecewise function]
2. [tex]3\sqrt{-[-(x-2)]+6}=3\sqrt{x-2+6}=3\sqrt{x+4}[/tex] when [ x-2<0→x<2]⇒[ Piecewise function]
We see there is a shape which is is in the form of dome,point of intersection of two curves being (2,7.348), symmetrical on both side of line x=2.
