nicolejlei nicolejlei
  • 26-02-2018
  • Chemistry
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How many moles of PbCl4 are needed to produce 2.00 g of Cl ions?

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Dejanras
Dejanras Dejanras
  • 07-03-2018
Answer is: 0,014 moles of PbCl₄ are needed.
Chemical dissociation: PbCl₄ → Pb⁴⁺ + 4Cl⁻.
m(Cl⁻) = 2,00 g.
n(Cl⁻) = m(Cl⁻) ÷ M(Cl⁻).
n(Cl⁻) = 2 g ÷ 35,45 g/mol.
n(Cl⁻) = 0,056 mol.
From chemical reaction: n(Cl⁻) : n(PbCl₄) = 4 : 1.
n(PbCl₄) = 0,056 mol ÷ 4.
n(PbCl₄) = 0,014 mol = 1,4·10⁻² mol.
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