Answer is: Volume of hydrogen sulfide is 131,37 L.
m(H₂S) = 200,0 g.
n(H₂S) = m(H₂S) ÷ M(H₂S).
n(H₂S) = 200 g ÷ 34,1 g/mol.
n(H₂S) = 5,865 mol.
V(H₂S) = n(H₂S) · Vm.
V(H₂S) = 5,865 mol · 22,4 L/mol.
V(H₂S) = 131,37 L = 131,37 dm³.
n - amount of substance.
Vm - molar volume.
