demonizedblue demonizedblue
  • 22-04-2018
  • Mathematics
contestada

In ΔABC, ∠CAD = 22° and segment CB = 15 cm. If the cos of 22° = 0.9272, then the sin of ∠C = _______.
-0.9272
0.9272
0.6537
-0.6537

In ΔABC CAD 22 and segment CB 15 cm If the cos of 22 09272 then the sin of C 09272 09272 06537 06537 class=

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19mccaba 19mccaba
  • 14-05-2018
Your answer is B. 0.9272. Hope I was able to help!
Answer Link
eudora eudora
  • 15-04-2019

Answer:

Option B. 0.9272

Step-by-step explanation:

In the given triangle ABC, ∠CAD = 22° segment CB = 15 cm.

We have to find sin of ∠C.

In the given triangle ADC,

∠CAD + ∠ADC + ∠DCA = 180

22° + 90° + ∠DCA = 180

∠DCA = 180 - 112 = 68°

Now we have to get the value of sinC or sin of angle DCA

Therefore sinC = sin 68° = 0.9272

Option B. 0.9272 is the correct option.

Answer Link

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