jetblackcap jetblackcap
  • 23-04-2018
  • Mathematics
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Аноним Аноним
  • 23-04-2018
(by + 2)/3 = c
by + 2 = 3c
by = 3c - 2
y = (3c - 2)/b

[tex]y = \frac{3c - 2}{b} [/tex]
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