The volume of a pyramid is one-third the product of the area of the base and the height of the pyramid.
V = (1/3)Ah
In this case, the base is a triangle whose area is
bh/2 = 12 cm * 10.4 cm/2 = 62.4 cm^2
V = (1/3)(62.4 cm^2)(9.8 cm)
V = 203.84 cm^3
Answer: 203.8 cm^3
