Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{0}{ h},\stackrel{0}{ k})\qquad \qquad radius=\stackrel{5}{ r} \\\\\\ (x-0)^2+(y-0)^2=5^2\implies x^2+y^2=25[/tex]

Answer:

The answer is D. x^2 + y^2=5^2 (APEX)

Step-by-step explanation:


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