Answer:
Option A. [tex]54\pi\ in^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the cylinder is equal
[tex]V=\pi r^{2}h[/tex]
where
r is the radius of the base of cylinder
h is the height of the cylinder
we have
[tex]r=3\ in[/tex]
[tex]h=6\ in[/tex]
substitute
[tex]V=\pi (3)^{2}(6)[/tex]
[tex]V=54\pi\ in^{3}[/tex]
