Respuesta :

carlosego
We have the following equation:
 x ^ 2- 6x + 7 = 0
 Step 1:
 Pass the constant term to the right:
 x ^ 2- 6x = - 7
 Step 2:
 Add (b / 2) ^ 2 to both sides of the equation:
 x ^ 2 - 6x + (-6/2) ^ 2 = - 7 + (-6/2) ^ 2
 x ^ 2 - 6x + (-3) ^ 2 = - 7 + (-3) ^ 2
 x ^ 2 - 6x + 9 = - 7 + 9
 x ^ 2 - 6x + 9 = 2
 Step 3:
 Rewrite polynomial:
 (x-3) ^ 2 = 2
 Step 4:
 Clear x:
 x-3 = +/- root (2)
 The solutions are:
 x1 = 3 + root (2)
 x2 = 3 - root (2)
 Answer:
 x1 = 3 + root (2)
 x2 = 3 - root (2)

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