"how many ways are there to construct a string of 3 digits if numbers cannot be repeated

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26-04-2018
Mathematics

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"how many ways are there to construct a string of 3 digits if numbers cannot be repeated

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musiclover10045 musiclover10045 · Answer 1 · 2018-04-26T14:00:31+02:00

musiclover10045 musiclover10045

26-04-2018

there are 10 total digits ( 0, 1 , 2, 3, 4, 5, 6, 7,8 ,9)

1st digit can be 1 of 10
2nd digit can be 1 of 9 ( 10-1 because a number cannot repeat)
3rd digit can be 1 of 8 ( 9-1 because no number can repeat)

total combinations = 10 * 9 * 8 = 720

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konrad509 konrad509 · Answer 2 · 2018-08-12T13:58:05+02:00

konrad509 konrad509

12-08-2018

[tex] \underbrace{10}_{\text{1 of 10 digits}}\cdot \underbrace{9}_{\text{1 of remaining 9 digits}}\cdot \underbrace{8}_{\text{1 of remaining 8 digits}}=720 [/tex]

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