[tex]Heya \: \: ! \\ \\
We \: \: know \: \: that \: \\ \\ \sqrt{16 } > \sqrt{15} > \sqrt{9} \\ \\ 4 > \sqrt{15} > 3 \\ \\ From \: the \: above \: numbers \: in \: \\ square \: root \: , \: it's \: clear \: that \: \\ \\ 4 \: \: is \: \: the \: \: closest \: \: integer \: to \: \sqrt{15} [/tex]
