Step-by-step explanation:
Given :
log(a) + log(b) + log(c) = log(a + b + c)
We know that by property
log(a) + log(b) + log(c) = log(abc)
Therefore,
log(abc) = log(a + b + c)
Thus,
(abc) = (a + b + c)
Thus when a = b = c = 0,
then (abc) = (a + b + c)
0 = 0
and when a = 1, b = 2, c = 3,
then (abc) = (a + b + c)
(1 x 2 x 3 ) = (1 + 2 + 3)
6 = 6
